Geometry | Professor Porua https://www.professorporua.squaryum.com Squaryum's Educational Guide Sun, 19 Jan 2025 11:15:53 +0000 en-US hourly 1 https://wordpress.org/?v=6.7.1 https://www.professorporua.squaryum.com/wp-content/uploads/2024/01/cropped-Logo-500-32x32.png Geometry | Professor Porua https://www.professorporua.squaryum.com 32 32 Pythagoras Theorem https://www.professorporua.squaryum.com/pythagoras-theorem/ Thu, 25 Jan 2024 11:15:37 +0000 https://www.professorporua.squaryum.com/?p=394

If, ∠ABC = 90° (AB & BC is perpendicular to each other), then:

(AC)² = (AB)² + (BC)²

OR

c² = a² + b²

OR

(Hypotenuse)² = (Perpendicular)² + (Base)²

]]> Area Perimeter https://www.professorporua.squaryum.com/area-perimeter/ Wed, 24 Jan 2024 07:46:32 +0000 https://www.professorporua.squaryum.com/?p=368

Circle

Rectangle

Square

Triangle

]]> Types of Triangle https://www.professorporua.squaryum.com/types-of-triangle/ Mon, 22 Jan 2024 14:46:47 +0000 https://www.professorporua.squaryum.com/?p=333

Geometry: Chapter 2

Types Of Triangle

Suppose ΔABC is a triangle. Then, depending on sides:

Equilateral Triangle:

AB=CD=AC
(all 3 sides of a triangle are equal)

Isosceles Triangle:

AB=AC or AB=BC or BC=AC
(any 2 sides of a triangle are equal)

Scalene Triangle:

None of the sides of a triangle are equal

Suppose the given diagram is a triangle (a+b+c=180°). Then, depending on angles:

Acute-Angled Triangle:

a<90°, b<90°, c<90°
(all 3 angles of a triangle are less than 90°)

Right-Angled Triangle:

a=90° or b=90° or c=90°
(any 1 angle of a triangle is 90°)

Obtuse-Angled Triangle:

a>90° or b>90° or c>90°
(any 1 angle of a triangle is more than 90°)

]]> Angles https://www.professorporua.squaryum.com/angles/ Mon, 22 Jan 2024 12:09:00 +0000 https://www.professorporua.squaryum.com/?p=319

To prove that AB is parallel to CD (AB||CD), where EF is a Transversal Line (the line that cuts across 2 other lines), we can use the help of following types of angles:

Corresponding Angles:

m=q | n=r | o=s | p=t

Alternate Interior Angles:

r=p | q=o

Alternate Exterior Angles:

t=n | s=m

Supplementary Angles:

r + o = 180° | q + p = 180°

Vertically Opposite Angles:

m=o | n=p | q=s | r=t

 

 

Moreover, since AB, CD & EF are straight lines, so:

 

m + n = 180° | n + o = 180° | o + p = 180° | p + m = 180°
q + r = 180° | r + s = 180° | s + t = 180° | t + q = 180°
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