Mathematics | Professor Porua https://www.professorporua.squaryum.com Squaryum's Educational Guide Sun, 19 Jan 2025 10:08:28 +0000 en-US hourly 1 https://wordpress.org/?v=6.7.1 https://www.professorporua.squaryum.com/wp-content/uploads/2024/01/cropped-Logo-500-32x32.png Mathematics | Professor Porua https://www.professorporua.squaryum.com 32 32 Simple Interest https://www.professorporua.squaryum.com/simple-interest/ Thu, 25 Jan 2024 11:52:30 +0000 https://www.professorporua.squaryum.com/?p=406

Suppose P is the initial amount (which is lent, deposited, invested or principal), t is the time or tenure & r is rate of interest, then Simple Interest (SI) can be calculated as below:

From the above formula, Principal (P), Rate (r) & Time (t) can be calculated as follows:

And, final Amount (A) can be calculated as:

Example:

Suppose a certain sum of money is deposited at 5% per annum Simple Interest, which amounted to Rs. 50,000 after 10 years. Then the sum of money can be calculated by the following:

Amount = A = Rs. 50,000

Rate = r = 5

Time = t = 10

Therefore, Principal = P = the sum of money = A/(1+((t x r)/100)) = 50000/(1+((10 x 5)/100)) = 50000/(1+(5/10)) = (50000 x 10)/15 = Rs. 33,333.33

and. Simple Interest = SI = A-P = 50000 – 33333.33 = Rs. 16,666.67

]]> BODMAS https://www.professorporua.squaryum.com/bodmas/ Thu, 25 Jan 2024 11:03:43 +0000 https://www.professorporua.squaryum.com/?p=389

Step 1:

Look for brackets and complete the calculations inside them, according bracket order:

FIRST    SECOND    THIRD

 

Step 2:

Look for any kind of roots (square roots, cube roots and others), indices (square of a number, cube of a number and others), exponents and powers.

 

Step 3:

Look for any kind of division and solve the calculations.

 

Step 4:

Look for any kind of multiplications and solve the calculations.

 

Step 5:

Look for any kind of additions and solve the calculations.

 

Step 6:

Look for any kind of subtractions and solve the calculations.

]]> Upstream & Downstream https://www.professorporua.squaryum.com/upstream-downstream/ Mon, 22 Jan 2024 17:20:45 +0000 https://www.professorporua.squaryum.com/?p=338

Upstream:

Boat is moving against the direction of water.

Suppose, u is the speed of boat in still water & v is the speed of stream, then:

Upstream Speed (x) = (u-v)km/hr

Downstream:

Boat is moving along the direction of water.

Suppose, u is the speed of boat in still water & v is the speed of stream, then:

Downstream Speed (y) = (u+v)km/hr

Speed Of Boat In Still Water:

0.5(y+x)

Speed Of Stream:

0.5(y-x)

Suppose, u is the upstream speed, v is the downstream speed and w is the speed of boat in still water. Then:

Suppose a boat takes n hours to travel from 1 point to another and back to the same point, where u is the speed of boat in still water & v is the speed of stream. Then:

Suppose a boat takes n1 hours to travel a distance and n2 hours to return the same distance, where v is the speed of stream. Then:

Suppose a boat takes n hours more, in case of upstream, than downstream, u is the speed of boat in still water and v is the speed of stream. Then:

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